写一个可以输入任意数字关于加减乘除的调用构造函数的c++代码

```c #include <stdio.h> typedef struct { int num1; int num2; char operator; } Calculator; Calculator create_calculator(int num1, int num2, char operator) { Calculator calculator; calculator.num1 = num1; calculator.num2 = num2; calculator.operator = operator; return calculator; } double calculate(Calculator calculator) { switch (calculator.operator) { case '+': return calculator.num1 + calculator.num2; case '-': return calculator.num1 - calculator.num2; case '*': return calculator.num1 * calculator.num2; case '/': if (calculator.num2 == 0) { printf("除数不能为0! "); return 0; } return (double)calculator.num1 / calculator.num2; default: printf("无效的操作符！ "); return 0; } } int main() { int num1, num2; char operator; printf("请输入两个数字和一个操作符(如：1 + 2):"); scanf("%d %d %c", &num1, &num2, &operator); Calculator calculator = create_calculator(num1, num2, operator); double result = calculate(calculator); printf("结果是：%.2lf ", result); return 0; } ```