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写一个可以输入任意数字关于加减乘除的调用构造函数的c++代码
原始问题:

写一个可以输入任意数字关于加减乘除的调用构造函数的c++代码

#include <stdio.h>

typedef struct {
    int num1;
    int num2;
    char operator;
} Calculator;

Calculator create_calculator(int num1, int num2, char operator) {
    Calculator calculator;
    calculator.num1 = num1;
    calculator.num2 = num2;
    calculator.operator = operator;
    return calculator;
}

double calculate(Calculator calculator) {
    switch (calculator.operator) {
        case '+':
            return calculator.num1 + calculator.num2;
        case '-':
            return calculator.num1 - calculator.num2;
        case '*':
            return calculator.num1 * calculator.num2;
        case '/':
            if (calculator.num2 == 0) {
                printf("除数不能为0!
");
                return 0;
            }
            return (double)calculator.num1 / calculator.num2;
        default:
            printf("无效的操作符!
");
            return 0;
    }
}

int main() {
    int num1, num2;
    char operator;
    printf("请输入两个数字和一个操作符(如:1 + 2):");
    scanf("%d %d %c", &num1, &num2, &operator);

    Calculator calculator = create_calculator(num1, num2, operator);
    double result = calculate(calculator);
    printf("结果是:%.2lf
", result);

    return 0;
}
写一个可以输入任意数字关于加减乘除的调用构造函数的c++代码
AI / 模型Siliconflow
时间 / DATESeptember 25, 2023, 10:05 AM
语言zh-CN
IP / 区域四川 成都